Population Standard Deviation | 150.0000 |
Sample Size | 18 |
Sample Mean | 554.6111 |
Confidence Interval | |
Confidence Coefficient | 0.95 |
Lower Limit | |
Upper Limit | |
Hypothesis Test | |
Hypothesized Value | 660 |
Test Statistic | |
P-value (Lower Tail) | 0.0014 |
P-value (Upper Tail) | |
P-value (Two Tail) |
Sample Size | 18 |
Sample Mean | 554.6111 |
Sample Standard Deviation | 162.8316 |
Confidence Interval | |
Confidence Coefficient | 0.95 |
Lower Limit | |
Upper Limit | |
Hypothesis Test | |
Hypothesized Value | 660 |
Test Statistic | |
P-value (Lower Tail) | 0.0069 |
P-value (Upper Tail) | |
P-value (Two Tail) |
The Hospital Care Cost Institute randomly selected 18 individuals, recorded the amount spent each year on prescription drugs, then put this information into Excel. Assume a population standard deviation of $150. Can you reject the hypothesis that the average amount spent per person each year on prescription drugs is at least $660 at α=.005? Based on this paragraph of text, use the correct excel output above to answer the following question.
For the hypothesis stated above, what is the conclusion?
a. |
There is significant evidence to conclude that the average amount spent per person each year on prescription drugs is less than $660. |
|
b. |
None of the answers is correct |
|
c. |
There is not significant evidence to conclude that the average amount spent per person each year on prescription drugs is more than $660. |
|
d. |
There is significant evidence to conclude that the average amount spent per person each year on prescription drugs is more than $660. |
|
e. |
There is not significant evidence to conclude that the average amount spent per person each year on prescription drugs is less than $660. |
Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ = 660
Alternative Hypothesis, Ha: μ < 660
Rejection Region
This is left tailed test, for α = 0.005
Critical value of z is -2.576.
Hence reject H0 if z < -2.576
Test statistic,
z = (xbar - mu)/(sigma/sqrt(n))
z = (554.6111 - 660)/(150/sqrt(18))
z = -2.98
P-value Approach
P-value = 0.0014
As P-value < 0.005, reject the null hypothesis.
There is significant evidence to conclude that the average
amount spent per person each year on prescription drugs is less
than $660.
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