Question
To test whether or not there is a difference between treatments A, B, and C, a...
To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below
| Treatment | Observations | |||
| A | 20 | 30 | 25 | 33 |
| B | 22 | 26 | 20 | 28 |
| C | 40 | 30 | 28 |
22 |
The mean square due to treatments (MSTR) equals
The null hypothesis for this ANOVA problem is
| The null hypothesis is to be tested at the 1% level of significance. The null hypothesis | ||
| a. |
should be rejected. |
|
| b. |
should not be rejected. |
|
| c. |
should be revised. |
|
| d. |
should not be tested |
|
Homework Answers
Answer #1
| Data Summary | ||||
|---|---|---|---|---|
| Groups | N | Mean | Std. Dev. | Std. Error |
| A | 4 | 27 | 5.7155 | 2.8577 |
| B | 4 | 24 | 3.6515 | 1.8257 |
| C | 4 | 30 | 7.4833 | 3.7417 |
| ANOVA Summary | |||||
|---|---|---|---|---|---|
| Source | Degrees of Freedom DF |
Sum of Squares SS |
Mean Square MS |
F-Stat | P-Value |
| Between Groups | 2 | 72 | 36 | 1.0588 | 0.3864 |
| Within Groups | 9 | 306.0005 | 34.0001 | ||
| Total: | 11 | 378.0005 |
The mean square due to treatments = 36
The null and alternate hypothesis
H0:
H1:
P value = 0.3864
Since p value greater than level of significance so we fail to reject the null hypothesis.
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