Question

23. Suppose the classes for an organized set of data are as follows: please fill in...

23. Suppose the classes for an organized set of data are as follows: please fill in the A column and answer B and C.

Class

A.

B.

C.

Mid-Point

What is the value of class width?

Into which class is the value 1.515 assigned?

0.235 – 0.875

0.875 – 1.515

1.515 – 2.155

24.Please fill in the blank and answer the following questions:

SUMMARY OUTPUT

Regression Statistics

Multiple R

__________

R Square

__________

Adjusted R Square

0.125

Standard Error

__________

Observations

__________

ANOVA

df

SS

MS

F

Significance F

Regression

1

0.828

__________

__________

0.2308

Residual

__________

2.227

__________

Total

6

__________

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Lower 95.0%

Upper 95.0%

Intercept

112.413

9.484

11.853

7.52722E-05

88.033

136.793

_____

__________

X

-19.137

14.033

-1.364

0.231

-55.211

16.937

___

__________

What is the coefficient of determination?

What is the coefficient of correlation?

Interpret the coefficient of determination

Interpret the coefficient of correlation

Homework Answers

Answer #1

23)

Mid point = (Lower Limit + Upper limit)/2

Class Width = Upper Limit – Lower Limit = 0.875 – 0.235 = 0.64

24)

For ANOVA Table:

Df Residual = df Total – df Regression

MS Regression = SS Regression / df Regression

MS Residual = SS Residual / df Residual

F = MS Regression/ MS Residual

SS Total = SS Regression + SS Residual

Completed Tables:

For Regression Summary,

R Square = SS Regression / SS Total

Multiple R = - Sqrt(R Square)

Standard Error = Sqrt(MS Residual)

Observations = df Total + 1

Coefficient of determination is 0.271. It means than 27% of the variation in the dependent variable is explained by the independent variable.


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