23. Suppose the classes for an organized set of data are as follows: please fill in the A column and answer B and C.
Class |
A. |
B. |
C. |
Mid-Point |
What is the value of class width? |
Into which class is the value 1.515 assigned? |
|
0.235 – 0.875 |
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0.875 – 1.515 |
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1.515 – 2.155 |
24.Please fill in the blank and answer the following questions:
SUMMARY OUTPUT |
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Regression Statistics |
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Multiple R |
__________ |
|||||||||||
R Square |
__________ |
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Adjusted R Square |
0.125 |
|||||||||||
Standard Error |
__________ |
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Observations |
__________ |
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ANOVA |
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df |
SS |
MS |
F |
Significance F |
||||||||
Regression |
1 |
0.828 |
__________ |
__________ |
0.2308 |
|||||||
Residual |
__________ |
2.227 |
__________ |
|||||||||
Total |
6 |
__________ |
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Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
Lower 95.0% |
Upper 95.0% |
|||||
Intercept |
112.413 |
9.484 |
11.853 |
7.52722E-05 |
88.033 |
136.793 |
_____ |
__________ |
||||
X |
-19.137 |
14.033 |
-1.364 |
0.231 |
-55.211 |
16.937 |
___ |
__________ |
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What is the coefficient of determination? |
What is the coefficient of correlation? |
Interpret the coefficient of determination |
Interpret the coefficient of correlation |
23)
Mid point = (Lower Limit + Upper limit)/2
Class Width = Upper Limit – Lower Limit = 0.875 – 0.235 = 0.64
24)
For ANOVA Table:
Df Residual = df Total – df Regression
MS Regression = SS Regression / df Regression
MS Residual = SS Residual / df Residual
F = MS Regression/ MS Residual
SS Total = SS Regression + SS Residual
Completed Tables:
For Regression Summary,
R Square = SS Regression / SS Total
Multiple R = - Sqrt(R Square)
Standard Error = Sqrt(MS Residual)
Observations = df Total + 1
Coefficient of determination is 0.271. It means than 27% of the variation in the dependent variable is explained by the independent variable.
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