Question

A survey wanted to determine what kind of game system was preferred by students. In a...

A survey wanted to determine what kind of game system was preferred by students. In a

survey of 150 students, 126 indicated that they preferred Xbox. Calculate and interpret a 99%

confidence interval for the proportion of all students who preferred Xbox.

Homework Answers

Answer #1

The 99% Confidence interval for the proportion of students who preferred Xbox (P) is given by -

where, n is the sample size = 150

p is the sample proportion of students who preferred Xbox  

= 0.84

is the critical value of z for the two tailed test at 0.01 level of significance = 2.58 as obtained from the z table.

Putting all these values in the formula of confidence interval, we get,

= [ 0.763, 0.917]

Hence, we are 99% confident that the Proportion of students who preferred Xbox is between 0.763 and 0.917.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The Student Recreation Center wanted to determine what sort of physical activity was preferred by students....
The Student Recreation Center wanted to determine what sort of physical activity was preferred by students. In a survey of 58 students, 41 indicated that they preferred outdoor exercise over exercising in a gym. When estimating the proportion of all students at the university who prefer outdoor exercise with 99% confidence, what is the margin of error? Question 8 options: 1) 0.1542 2) 0.0202 3) 0.0598 4) 0.0092 5) 0.1393
Mr Stat wanted to determine the population proportion of students who drop out of his statistics...
Mr Stat wanted to determine the population proportion of students who drop out of his statistics course. He finds of the 160 students who started the term, 32 stopped attending. Find a 99% confidence interval for the population proportion of students who drop statistics. Interpret your answer. Part A - Fill out the pieces of the formula:    times the square root of ( times divided by ) Part B - To two decimal places, the interval is ( ,...
The Dean of Students at a large university wanted to estimate the proportion of students who...
The Dean of Students at a large university wanted to estimate the proportion of students who are willing to report cheating by fellow students. So, her staff surveyed 172 students currently enrolled in the introduction to biology class. The students were asked, “Imagine that you witness two students cheating on a quiz. Would you tell the professor?” 19 of the surveyed students responded “yes.” Using these data, calculate a 95% confidence interval for the proportion of all students at the...
Out of a sample of 180 students, 85 indicated that they preferred chocolate ice cream to...
Out of a sample of 180 students, 85 indicated that they preferred chocolate ice cream to vanilla ice cream. a. Estimate the value of the population proportion of those who preferred chocolate ice cream. (Round the final answer to 3 decimal places.) Estimated population proportion    b. Compute the standard error of the proportion. (Round the final answer to 4 decimal places.) Standard error of the proportion    c. Determine a 80% confidence interval for the population proportion of those...
For our survey of Stat 281 students, there are 119 out of 318 students from the...
For our survey of Stat 281 students, there are 119 out of 318 students from the College of Agriculture & Biological sciences. a. Calculate the sampling proportion p that are from College of Agriculture & Biological Sciences, then find out what is the standard error of p and the sampling distribution for p approximately normal? b. Calculate a 95% confidence interval for proportion of students who are in the College of agriculture and Biological sciences in your stats class. then...
In a recent survey of 200 elementary students, many revealed they preferred math than English. Suppose...
In a recent survey of 200 elementary students, many revealed they preferred math than English. Suppose that 80 of the students surveyed were girls and that 120 of them were boys. In the survey, 60 of the girls, and 80 of the boys said that they preferred math more. 3) Calculate an 80% confidence interval for the difference in proportions 4) Suppose the 90% confidence interval for the difference in proportion is (-0.0232, 0.1899). Is the following interpretation of the...
1.A survey of households in a small town showed that in 850 of 1,200 sampled households,...
1.A survey of households in a small town showed that in 850 of 1,200 sampled households, at least one member attended a town meeting during the year. Using the 99% level of confidence, what is the confidence interval for the proportion of households represented at a town meeting? 2.A survey of an urban university (population of 25,450) showed that 750 of 1,100 students sampled attended a home football game during the season. Using the 99% level of confidence, what is...
A survey is given to 300 random SCSU students to determine their opinion of being a...
A survey is given to 300 random SCSU students to determine their opinion of being a “Tobacco Free Campus.” Of the 300 students surveyed, 230 were in favor a tobacco free campus. a. Find a 95% confidence interval for the proportion of all SCSU students in favor of a tobacco free campus. b. Interpret the interval in part a. c. Find the error bound of the interval in part a. d. The Dean claims that at least 70% of all...
In a survey of 4010 ​adults, 727 oppose allowing transgender students to use the bathrooms of...
In a survey of 4010 ​adults, 727 oppose allowing transgender students to use the bathrooms of the opposite biological sex. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is ​( nothing ​, nothing ​). ​(Round to three decimal places as​ needed.)
Out of a sample of 200 students, 75 indicated that they preferred chocolate ice cream to...
Out of a sample of 200 students, 75 indicated that they preferred chocolate ice cream to vanilla ice cream. a. Estimate the value of the population proportion of those who preferred chocolate ice cream. (Round the final answer to 3 decimal places.)       Estimated population proportion        b. Compute the standard error of the proportion. (Round the final answer to 4 decimal places.)   Standard error of the proportion    c. Determine a 90% confidence interval for the population proportion...