Three different modalities were tested for delivering a newly-developed product training course at YU Limited. The Company selected 21 sales associates and randomly assigned them to one of the three modalities for training. The file BUSI 1013 ANOVA.xlsx contains results of a product knowledge test at the end of the training. Use this data for a statistical test to see whether the three modalities are not equally effective in that the mean score of the product knowledge test are not the same for the three modalities. Use 0.05 as the level of significance
Table:
Classroom |
Online |
Mixed Mode |
78 |
77 |
69 |
85 |
88 |
78 |
76 |
92 |
80 |
85 |
83 |
66 |
85 |
86 |
67 |
74 |
75 |
76 |
91 |
93 |
92 |
Answer:
We can directly use here one way anova by Excel.
Step1) Enter data in Excel.
Step 2) Data >>Data analysis >> One way anova >>Select data >>click on label in first row >>ok
Null hypothesis
vs
Alternative hypothesis
H1: Not all three means are equal.
P value is 0.0815 > 0.05
Therefore, we fail to reject H0.
We do not have enough evidence to reject the null hypothesis and conclude that the population means are all equal.
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