Question

In​ randomized, double-blind clinical trials of a new​ vaccine, children were randomly divided into two groups. Subjects in group 1 received the new vaccine while subjects in group 2 received a control vaccine. After the first​ dose, 101 of 744 subjects in the experimental group​ (group 1) experienced vomiting as a side effect. After the first​ dose, 60 of 635 of the subjects in the control group​ (group 2) experienced vomiting as a side effect. Construct a 99​% confidence interval for the difference between the two population​ proportions, p 1 minus p 2. Use x 1 equals101​, n 1 equals744​, x 2 equals60​, and n 2 equals635. The 99​% confidence interval for p 1 minus p 2 is ​( nothing​, nothing​). ​(Use ascending order. Round to three decimal places as​ needed.)

Answer 1

Solution:

Given

n1= 744

n2= 635

P1 = 101/744 = 0.1357

P2 = 60/635 = 0.0944

Level

So, the 99 % confidence interval is

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