Question

Suppose you play a game with a friend and the probability of losing is 6/11 The odds against losing would be

Answer 1

We know the formula of odds against any event E is given by P[not E)/P(E)].

Odds against E = P(not E)/P(E) = P(E')/P(E)

Here, E is the event of losing the game.

It is given that the probability of losing is 6/11. So, we can see that P(E) = 6/11

We know that,

P(event occuring)+P(event not occuring) = 1

or, P(E) + P(E') = 1 or, P(E') = 1 - P(E)

Thus, P(E') = 1 - (6/11) = 5/11

Thus, P(E) = 6/11 and P(E') = 5/11

Now, odds against E = P(E')/P(E) = (5/11)/(6/11) = 5/6

Thus, odds against losing = 5/6 = 0.833 .