7/10 red candies, randomly pick 4, what is the probability that 2 or more of these 4 are red candies?
This is a direct application of Binomial distribution,
Let X be a number of red candies among 4 candies.
P(red candies) = 7/10 = 0.7
Here, X ~ Binomial ( n = 4, p = 0.7)
Probability mass function of X is,
P(X = x) = nCx px (1-p)n-x
We want to find, P(X >= 2)
P(X >= 2)
= 1 - P(X <= 1)
= 1 - [ P(X = 0) + P(X = 1) ]
= 1 - [ 0.0081 + 0.0756 ]
= 1 - 0.0837
= 0.9163
P( X >= 2) = 0.9163
Hence, the probability that 2 or more of these 4 are red candies is 0.9163
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