Question

A sample of six records for repairs of a component showed the following costs: 93 97...

A sample of six records for repairs of a component showed the following costs: 93 97 89 79 81 87 Construct a 90% confidence interval for the standard deviation of the repair cost of this type of component. Assume that repair costs are normally distributed.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of six records for repairs of a component showed the following costs: 93 97...
A sample of six records for repairs of a component showed the following costs: 93 97 89 79 81 87 Construct a 90% confidence interval for the standard deviation of the repair cost of this type of component. Assume that repair costs are normally distributed.
In a random sample of six mobile devices, the mean repair cost was $60.00 and the...
In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population μ is (_, _)
In a random sample of six mobile​ devices, the mean repair cost was $75.00 and the...
In a random sample of six mobile​ devices, the mean repair cost was $75.00 and the standard deviation was $13.0013.00. Assume the population is normally distributed and use a​ t-distribution to find the margin of error and construct a 95​% confidence interval for the population mean. Interpret the results. The 95​% confidence interval for the population mean μ is
A researcher records the repair cost for 20 randomly selected stereos. A sample mean of $57.17...
A researcher records the repair cost for 20 randomly selected stereos. A sample mean of $57.17 and standard deviation of $19.26 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the stereos. Assume the population is approximately normal. Step 2 of 2 : Construct the 90%90% confidence interval. Round your answer to two decimal places.
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46...
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the washers. Assume the population is approximately normal. Step 2 of 2: Construct the 90% confidence interval. Round your answer to two decimal places.
The following is a sample of sanitation scores for 20 cruise ships. 97, 88, 81, 87,...
The following is a sample of sanitation scores for 20 cruise ships. 97, 88, 81, 87, 90, 89, 82, 88, 92, 92, 86, 82, 99, 86, 93, 82, 94, 90, 89, 92 A) Find the mean and standard deviation of the sanitation scores. x = _____ S = _____ B) Calculate the intervals x̅ ± s , x̅ ± 2s, x̅ ±​​​​​​​ 3s : x̅ ± s = ( ___ , ___ ) x̅ ±​​​​​​​ 2s = ( ___ ,...
A consumer affairs investigator records the repair cost for 44 randomly selected TVs. A sample mean...
A consumer affairs investigator records the repair cost for 44 randomly selected TVs. A sample mean of $54.41 and standard deviation of $28.89 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the TVs. Assume the population is approximately normal. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places. Step 2 of 2: Construct the 90% confidence interval. Round your...
In a random sample of six ​people, the mean driving distance to work was 18.3 miles...
In a random sample of six ​people, the mean driving distance to work was 18.3 miles and the standard deviation was 4.3 miles. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a 90​% confidence interval for the population mean mu. Interpret the results. Identify the margin of error.
a random sample of 40 transmission replavement costs find the mean to be $2520.00. Assume the...
a random sample of 40 transmission replavement costs find the mean to be $2520.00. Assume the population standard deviation is $400.00. A 95% confidence interval for the population mean repair cost is (2396.0,2644.0) Change the sample to n=80. Construct a 95% confidence interval for the population mean repair cost. which confidence interval its wider?
A manager records the repair cost for 14 randomly selected dryers. A sample mean of $88.34...
A manager records the repair cost for 14 randomly selected dryers. A sample mean of $88.34 and standard deviation of $19.22 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the dryers. Assume the population is approximately normal. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT