Question

You wish to estimate the proportion of adults that have ever used alternative medicine. Obtain a...

You wish to estimate the proportion of adults that have ever used alternative medicine. Obtain a sample size that will ensure a margin of error of at most 0.01 for a 95% confidence interval. It is deemed reasonable to presume that of those sampled, the proportion that have used alternative medicine will be at least 0.64? Round to a whole number.

Homework Answers

Answer #1

Solution :

Given that,

= 0.64

1 - = 1 - 0.64= 0.36

margin of error = E =0.01

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (1.96 / 0.01)2 * 0.64 * 0.36

= 8851.0464

Sample size =8851

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