Solution(a)
Given in the question
Degree of freedom for treatment = 2,
So total no. pf individual group = DF for treatment +1 = 2+1 =
3
Solution(b)
Degree of freedom for Error = 18
So total degree of freedom = 18+2 = 20
So total number of observation = 20+1 = 21
Solution(c)
At ftest stat = 5.84
DF numerator = 2
DF denominator = 18
So p-value from F table is = 0.0111
As we can see that p-value is greater than alpha value so we are
failed to reject the null hypothesis.
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