"Find the 95% confidence interval lower limit for the mean when the sample mean is equal to 69, the standard deviation is known to be 17, and the sample size is 9"
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Answer:
Given that:
Find the 95% confidence interval lower limit for the mean when the sample mean is equal to 69, the standard deviation is known to be 17, and the sample size is 9
95% confidence Interval for mean
X bar = 69, sigma= 17 , alpha = 0.05 , Z critical = 1.96
Sample size = n = 9
X bar +/- [ Z c * sigma / sqrt( n ) ]
69 +/- [ 1.96* 17 / sqrt ( 9 ) ]
69 +/- [ 1.96* 17 / 3]
69 +/- [ 1.96* 5.66]
69 +/- 11.09
69 - 11,09 < mu < 69 + 11.09
57.91 < mu < 80.09
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