Question

A volleyball coach noted that players who practices jumping during practice time seemed to be able to jump higher in the games. He wondered if jumping practice was more or less effective than lower extremely weight training to increase vertical jump height. To test this phenomena, he proposed the null hypothesis, that there are no significant differences between players who practices jumping, players who practice in lower extremity weight training, and players who do neither exercise.

Control Group 23, 21, 15, 16, 31 Weight Training Group 36, 45, 48, 40, 54 Jumping Practice Group 33, 22, 36, 29, 27

=. What is the F value? ________________ Is it significant? _____________ If so, what is the p value? __________________



=. For this F test, what is a recommended F-value to be statistically significant at .05 level? ______________________



=. Do you accept or reject the null hypothesis? Explain why.   



=. Conclude your findings in a statistical term.

Answer 1

Applying one way ANOVA on above data:

Source of Variation	SS	df	MS	F	P-value
Between Groups	1409.733	2	704.867	17.725	0.0003
Within Groups	477.200	12	39.767
Total	1886.933	14

from above:

F value =17.725~ 17.73

Is it significant? :Yes

p value =0.0003

recommended F-value to be statistically significant at .05 level =3.885

Do you accept or reject the null hypothesis? :Reject Ho

. Conclude your findings in a statistical term. - p value <0.05, conclude that there is a significant differences in mean time between three excercise groups