A test of the null hypothesis
H0: μ = μ0
gives test statistic
z = −1.24.
(Round your answers to four decimal places.)
(a) What is the P-value if the alternative is
Ha: μ > μ0?
(b) What is the P-value if the alternative is
Ha: μ < μ0?
(c) What is the P-value if the alternative is
Ha: μ ≠ μ0?
Solution :
Given that,
z = - 1.24
Using standard normal table,
p value = 0.1075
a ) P(z > - 1.24 )
This is the right tailed test .
1 - P(z < - 1.24)
= 1 - 0.1075
= 0.8925
P-value = 0.8925
Reject the null hypothesis .
b ) P(z < - 1.24) = 0.1075
This is the left tailed test .
Do not reject the null hypothesis .
c ) This is the two tailed test ,
Using standard normal table,
P-value = 2 * P(z > 2.58)
= 2 * 0.8925
= 1.785
P-value = 1.785
Reject the null hypothesis
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