It is believed that on average 40 % of all children have some kind of nut allergy. A kindergarten has registered 260 incoming children. With 95% certainty, what is the lowest number of children that will have any kind of nut allergy among the 260 incoming children. (Hint: 95% certainty is equivalent to 2 standard deviations above and below the mean).
Answer:
Given that:
It is believed that on average 40 % of all children have some kind of nut allergy. A kindergarten has registered 260 incoming children.
With 95% certainty, what is the lowest number of children that will have any kind of nut allergy among the 260 incoming children.
We have 260 incoming children on average 40% have nut allergy.
So mean number of children having null allergy in the incoming ones
= 260 *0.40
= 104
Variance = 260^2 * 0.40 - (104)^2
= 67600 * 0.40 - 10816
= 27040 - 10816
= 16,224
Standard deviation =
=
=
Now, 95% certaintly equivalent is 2 S.D above and below in the meanSo the lowest number of children having allergy
=
=
=
=
=
The required number of children is 89.
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