One of the hot topics in the last presidential election was with respect to our citizen’s health and whether or not the government has a right to limit our choices in what we eat or drink. A random sample of 1046 Americans was obtained. The question asked was “Do you support our govern-ment banning specific types or sizes of food or drinks?” Of those surveyed, 895 responded, “no.”
a. Estimate with 95% confidence the proportion of Americans who do not support the govern-ment banning specific types or sizes of food or drinks.
b. Using the confidence interval found in part a, can you conclude that a majority of Americans do not support the government banning specific types or sizes of food or drinks. Why or why not
Part a
Confidence interval for Population Proportion is given as below:
Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)
Where, P is the sample proportion, Z is critical value, and n is sample size.
We are given
x = 895
n = 1046
P = x/n = 895/1046 = 0.855640535
Confidence level = 95%
Critical Z value = 1.96
(by using z-table)
Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)
Confidence Interval = .855640535 ± 1.96* sqrt(.855640535*(1 – .855640535)/1046)
Confidence Interval = .855640535 ± 1.96* 0.0109
Confidence Interval = .855640535 ± 0.0213
Lower limit = .855640535 - 0.0213 = 0.8343
Upper limit = .855640535 + 0.0213 = 0.8769
Confidence interval = (0.8343, 0.8769)
Part b
Yes, we can conclude that a majority of Americans do not support the government banning specific types of sizes of food or drinks, because this interval contains values more than 0.5.
Get Answers For Free
Most questions answered within 1 hours.