Question

Noah wants to advertise how many chocolate chips are in each Big Chip cookie at his...

Noah wants to advertise how many chocolate chips are in each Big Chip cookie at his bakery. He randomly selects a sample of 41 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 8.1 and a standard deviation of 1.8. What is the 80% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Assume the data is from a normally distributed population. Round answers to 3 decimal places where possible.

Homework Answers

Answer #1

Confidence interval for Population mean is given as below:

Confidence interval = Xbar ± t*S/sqrt(n)

From given data, we have

Xbar = 8.1

S = 1.8

n = 41

df = n – 1 = 40

Confidence level = 80%

Critical t value = 1.3031

(by using t-table)

Confidence interval = Xbar ± t*S/sqrt(n)

Confidence interval = 8.1 ± 1.3031*1.8/sqrt(41)

Confidence interval = 8.1 ± 0.3663

Lower limit = 8.1 - 0.3663 = 7.734

Upper limit = 8.1 + 0.3663 = 8.466

Confidence interval = (7.73, 8.466)

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