Question

**(a)**

**Construct a 95% confidence interval about**

**Mu μ if the sample size, n, is 34**

**Lower bound:**

**___________**

**; Upper bound:**

**______________**

**(Use ascending order. Round to two decimal places as
needed.)**

**(b) Construct a 95% confidence interval about mu μ if
the sample size, n, is 51.**

**Lower bound:**

**____________**

**; Upper bound:**

**____________**

**(Use ascending order. Round to two decimal places as
needed.)**

**How does increasing the sample size affect the margin
of error, E?**

**A.**

**The margin of error decreases.**

**B.**

**The margin of error does not change.**

**C.**

**The margin of error increases.**

**(c) Construct a 99% confidence interval about mu μ if
the sample size, n, is 34**

**Lower bound:**

**___________**

**; Upper bound:**

**________________**

**(Use ascending order. Round to two decimal places as
needed.)**

**Compare the results to those obtained in part (a). How
does increasing the level of confidence affect the size of the
margin of error, E?**

**A.**

**The margin of error decreases.**

**B.**

**The margin of error increases.**

**C.**

**The margin of error does not change.**

**(d) If the sample size is 13**

**, what conditions must be satisfied to compute the
confidence interval?**

**A.**

**The sample size must be large and the sample should not
have any outliers.**

**B.**

**The sample must come from a population that is normally
distributed and the sample size must be large.**

**C.**

**The sample data must come from a population that is
normally distributed with no outliers.**

Answer #1

**Answer:**

**a)** As xbar and standard deviation is given in
the question

Let us take an example:

**Xbar = 18.9
standard deviation =4.3**

Margin of error = 1.96 * 4.3/sqrt (34) = 1.445

Lower bound = 18.9 - 1.445 = 17.46

Upper bound = 18.9 + 1.445 = 20.25

**b)**

Margin of error = 1.96 * 4.3/sqrt (51) = 1.18

Lower bound = 18.9 - 1.18 = 17.72

Upper bound = 18.9 + 1.18 = 20.08

The increasing the sample size affect the margin oferror is

Margin of error decreases

**c)**

Margin of error = 2.575 * 4.3/sqrt (34) = 1.899

Lower bound = 18.9 - 1.889 = 17.01

Upper bound = 18.9 + 1.889 = 20.79

The margin of error increases

**d)**

For Computing the Confidence Interval sample size must be large.

Hence

The sample must come from a population that is normally distributed and the sample size must be large.

A simple random sample of size n is drawn. The sample mean, x
overbar, is found to be 17.6, and the sample standard deviation,
s, is found to be 4.1. LOADING... Click the icon to view the table
of areas under the t-distribution. (a) Construct a 95%
confidence interval about mu if the sample size, n, is 35. Lower
bound: nothing; Upper bound: nothing (Use ascending order. Round
to two decimal places as needed.) (b) Construct a 95% confidence
interval...

A simple random sample of size n is drawn. The sample mean, x
overbar, is found to be 17.7, and the sample standard deviation,
s, is found to be 4.8.
Click the icon to view the table of areas under the
t-distribution.
(a) Construct a 95% confidence interval about mu if the
sample size, n, is 35. Lower bound: nothing; Upper bound:
nothing (Use ascending order. Round to two decimal places as
needed.)
(b) Construct a 95% confidence interval about...

A simple random sample of size n is drawn. The sample mean, x
overbarx, is found to be 19.219.2, and the sample standard
deviation, s, is found to be 4.34.3. LOADING... Click the icon to
view the table of areas under the t-distribution. (a) Construct a
9595% confidence interval about muμ if the sample size, n, is
3535. Lower bound: nothingm; Upper bound: nothingm (Use
ascending order. Round to two decimal places as needed.) (b)
Construct a 9595% confidence interval...

A simple random sample of size n is drawn from a population that
is normally distributed. The sample mean,
x,
is found to be
115,
and the sample standard deviation, s, is found to be
10.
(a) Construct
a
95%
confidence interval about
μ
if the sample size, n, is
22.
(b) Construct
a
95%
confidence interval about
μ
if the sample size, n, is
12.
(c) Construct
a
90%
confidence interval about
μ
if the sample size, n, is...

A simple random sample of size n is drawn. The sample? mean,x is
found to be 17.6 and the sample standard? deviation, s, is found to
be
4.1
(a) Construct a 95% confidence interval about ? if the sample
size, n, is 34
The confidence interval is?
(b) Construct a 95% confidence interval about ? if the sample
size, n, is 61
The confidence interval is (?,?)
(use ascending order. Round to two decimal places as needed)
How does increasing...

A simple random sample of size n is drawn from a population that
is normally distributed. The sample mean, x bar over x, is found to
be 109, and the sample standard deviation, s, is found to be
10.
a) Construct a 96% confidence interval about mu if the sample
size, n, is 29
lower bound: __ upper bound: __
b) Re-do, but with a different interval. Construct a 95%
confidence interval about mu if sample size n, is 29...

A simple random sample of size n is drawn from a population that
is known to be normally distributed. The sample variance, s
squared, is determined to be 11.8. Complete parts (a) through
(c). (a) Construct a 90% confidence interval for sigma squared if
the sample size, n, is 20. The lower bound is nothing. (Round to
two decimal places as needed.) The upper bound is nothing. (Round
to two decimal places as needed.)
b) Construct a 90% confidence...

A simple random sample of size n is drawn from a population that
is known to be normally distributed. The sample variance, s
squared, is determined to be 13.4. Complete parts (a) through
(c). (a) Construct a 90% confidence interval for sigma squared if
the sample size, n, is 20. The lower bound is nothing. (Round to
two decimal places as needed.) The upper bound is nothing. (Round
to two decimal places as needed.) (b) Construct a 90% confidence
interval...

A simple random sample of size n is drawn from a population that
is known to be normally distributed. The sample variance,
s squareds2,
is determined to be
12.512.5.
Complete parts (a) through (c).
(a) Construct a 90% confidence interval for
sigma squaredσ2
if the sample size, n, is 20.The lower bound is
nothing.
(Round to two decimal places as needed.)The upper bound is
nothing.
(Round to two decimal places as needed.)(b) Construct a 90%
confidence interval for
sigma squaredσ2...

A simple random sample of size n is drawn from a population that
is normally distributed. The sample mean, x overbar, is found to
be 105, and the sample standard deviation, s, is found to be 10.
(a) Construct a 90% confidence interval about mu if the sample
size, n, is 24. (b) Construct a 90% confidence interval about mu
if the sample size, n, is 20. (c) Construct an 80% confidence
interval about mu if the sample size, n,...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 24 minutes ago

asked 30 minutes ago

asked 36 minutes ago

asked 41 minutes ago

asked 47 minutes ago

asked 47 minutes ago

asked 54 minutes ago

asked 54 minutes ago

asked 54 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago