a) As we are trying to test the claim here that the standard deviation of the pulse rate distribution is equal to 10, therefore the null and alternate hypothesis here are given as:
b) Now we are given the sample standard deviation here as s = 7.2 with sample size n = 31
The test statistic here is computed as:
Therefore 15.552 is the test statistic value required here.
c) Now as this is a two tailed test, the p-value for n - 1 = 30 degrees of freedom is computed from the chi square distribution tables as:
Therefore 0.0276 is the required p-value here.
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