13. Adult IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the probability that a randomly chosen adult has an IQ between 70 and 115.
Solution:
Given, X follows Normal distribution with,
= 100
= 15
P(70 < x< 115)
= P(X < 115) - P(X < 70)
= P[(X -
)/
< (115 - 100)/15] - P[(X -
)/
< (70 - 100)/15]
= P[Z < 1.00] - P[Z < -2.00]
= 0.8413 - 0.0228 ..Use z table
= 0.8185
Required Probability = 0.8185
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