Question

2. On the Canadian Senate there are 105 members, 58 are Conservative and 47 are Liberal....

2. On the Canadian Senate there are 105 members, 58 are Conservative and 47 are Liberal.

a) How many ways are there to select at least 2 Liberals for a sub-committee of 5 Senate members?

b) What is the probability of selecting 5 people for a sub-committee that contains 1 Liberals and 4 Conservatives?

c) What is the probability that no Liberals are selected in a sub-committee of 5 Senate members?

d) Suppose the 5 members in the sub-committee have rankings of President, Vice-President, Operations Officer, Press Secretary, and Treasurer. What is the probability of selecting all Liberals to these positions

Thanks! due tomorrow as well.

a) number of ways =P(at least 2 liberals)=N(2 liberal and 3 Conservative )+N(3 liberal and 2 Conservative )+N(4 liberal and 1 Conservative )+N(5 liberal and 0 Conservative )

=47C2*58C3 +47C3*58C2 +47C4*58C1 +47C5*58C0 =72037840

b) probability of selecting 5 people for a sub-committee that contains 1 Liberals and 4 Conservatives

=47C1*58C4 /105C5 =47*424270/96560646 =0.206509

c)

probability that no Liberals are selected in a sub-committee of 5 Senate members= 47C0*58C5 /105C5

=1*4582116/96560646 =0.047453

d)

probability of selecting all Liberals to these positions =47C5 /105C5 =1533939/96560646 =0.015886