The time spent waiting in the line is approximately normally distributed. The mean waiting time is 5 minutes and the variance of the waiting time is 9. Find the probability that a person will wait for less than 7 minutes. Round your answer to four decimal places.
Answer:
To determine the probability that a person will wait for less than 7 minutes
Given,
mean = = 5
variance = = 9
standard deviation = = 3
P(x < 7) = P((x - ) / )
substitute values
P(x < 7) = (P < (7 - 5) / 3)
= P(z < 0.667)
= 0.7476
Probability = 0.7476
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