Suppose that the level of education for everyone in the population has a normal distribution. Assume that the mean level of education is 12 years (HS degree) and the standard deviation is 2 years.
Given that, mean (μ) = 12 years and
standard deviation = 2 years
a) For x = 7.5
=> Z-score = -2.25
For x = 10
=> Z-score = -1
For x = 13.5
=> Z-score = 0.75
For x = 15
=> Z-score = 1.5
b) For z = -1
=> x = 10 years
For z = 0.5
=> x = 13 years
For z = 2.0
=> x = 16 years
c) We want to find, P(11.5 < X < 13)
In percentage : 0.2902 * 100 = 29.02%
Therefore, required percentage is 29.02%
Get Answers For Free
Most questions answered within 1 hours.