Assume that adults have IQ scores that are normally distributed with a mean of 200 and a standard deviation of 20. Find the probability that a randomly selected adult has an IQ between 150 and 175.
Given,
= 200 , = 20
We convert this to standard normal as
P( X < x) = P (Z < x - / )
So,
P(150 < X < 175) = P( X < 175) - P( X < 150)
= P( Z < 175 - 200 / 20) - P( Z < 150 - 200 / 20)
= P( Z < -1.25) - P( Z < -2.5)
= ( 1 - P (Z < 1.25) ) - ( 1 - P( Z < 2.5) )
= ( 1 - 0.8944) - P( 1 - 0.9938) (Probability calculated from Z table)
= 0.0994
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