Compute P(x) using the binomial probability formula. Then determine whether the normal distribution can be used to estimate this probability. If so, approximate P(x) using the normal distribution and compare the result with the exact probability. n equals = 81, p equals = 0.82 0.82, and x equals = 72
Using binomial probability:
for, n = 81 , p = 0.82 and x = 72
P[X=x] =
= 0.0322
Now, for Binomial (n,p) :
E(X) = np = 81 * 0.82 = 66.42
Var(X) = np(1-p) = 81*0.82*0.18 = 11.96
Using normal approximation : As n is 81, quite large, we can use normal approximation.
Now, P[X=72] = P[X<73]-P[X<72]
= P[Z<1.90] - P[Z<1.61]
= 0.9713 - 0.9463
= 0.025
So we can see that normal approximation under estimate the proability a bit, But it is still quite good approximation.
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