A new bowler bowled a strike 20% of the time she bowls a frame, but now she thinks that she increased the probability. This is her hypothesis: H(0) : π = .2 H(a) : π > .2 where π is the proportion of strikes she bowls. She bowls 120 frames and achieves 28 strikes. Find the test statistic.
Separately, she bowls 90 times and achieves 43 strikes. The hypothesis here is H(0) : π = .6 H(a) : π < .6 Find the test statistic.
1) p = 0.2
p^ = 28/120 = 0.233
test statistic
= 0.913
2) p = 0.6
p^ = 43 / 90
test statistic
= -2.367
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