Question

A researcher wanted to estimate the true proportion of smokers in a certain city (?). He...

A researcher wanted to estimate the true proportion of smokers in a certain city (?). He selected a random sample of size ? = 50 people and found 15 smokers in the sample. a) Find a point estimate for (?). b) Find a 95% confidence interval for (?). c) If we use the sample proportion (?̅) to estimate (?), calculate the margin of error using the confidence level 0.95

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Q. A researcher wanted to estimate the true proportion of smokers in a certain city (?)....
Q. A researcher wanted to estimate the true proportion of smokers in a certain city (?). He selected a random sample of size ? = 50 people and found 15 smokers in the sample. a) Find a point estimate for (?). b) Find a 95% confidence interval for (?). c) If we use the sample proportion (?̅) to estimate (?), calculate the margin of error using the confidence level 0.95.
An agronomist wanted to estimate the mean weight of a certain fruit (?) in his farm....
An agronomist wanted to estimate the mean weight of a certain fruit (?) in his farm. He selected a random sample of size ?=16, and found that the sample mean ?̅=55 gm and a sample stranded deviation ?= 3 gm. It is assumed that the population is normal with unknown standard deviation (?). a) Find a point estimate for (?). b) Find a 95% confidence interval for the population mean (?).
a researcher wishes to estimate the proportion of adults in the city of Darby who are...
a researcher wishes to estimate the proportion of adults in the city of Darby who are vegetarian. in a random sample of 1729 adults from the city's proportion that are vegetarian is 0.083. find a 95% confidence interval for the proportion of all adults in the city of Darby that are vegetarians.
1.A confidence interval was constructed to estimate the proportion of smokers in the U.S. Use the...
1.A confidence interval was constructed to estimate the proportion of smokers in the U.S. Use the confidence interval 0.117 < p < 0.412 to find the point estimate, p ^ . Round answer to 3 decimal places. 2.A confidence interval was constructed to estimate the proportion of people who suffer from seasonal allergy. Use the confidence interval 0.466 < p < 0.54 to find the point estimate, p ^ . Round answer to 3 decimal places. 3.A confidence interval was...
An estimate is needed of the mean acreage of farms in a certain city. A​ 95%...
An estimate is needed of the mean acreage of farms in a certain city. A​ 95% confidence interval should have a margin of error of 22 acres. A study ten years ago in this city had a sample standard deviation of 210 acres for farm size. acres for farm size. Answer parts ​(a​) and ​(b​). a. About how large a sample of farms is​ needed? n=? ​(Round up to the nearest​ integer.) b. A sample is selected of the size...
A researcher in a small town is interested in estimating the true proportion of adults in...
A researcher in a small town is interested in estimating the true proportion of adults in the town who smoke. 215 adults were randomly selected from the town, and it was found that 36 of them smoke. We would like to construct a 90% confidence interval estimate for the true proportion of adults in the town that smoke. please show work! thanks. What are the values of, , and  (Round  and  to three decimal places if needed.) = _______________                 = _______________ = _______________                 = _______________...
Let's say we want to estimate the population proportion of a population. A simple random sample...
Let's say we want to estimate the population proportion of a population. A simple random sample of size 400 is taken from the population. If the sample proportion is 0.32: 1) what is the point estimate of the population proportion? 2) At the 95% level of confidence, what is the margin of error? 3) Based on 2) what is a confidence interval at the 95% confidence level? 4) What is the margin of error if the level of confidence is...
A medical researcher wanted to estimate the proportion of all births in the United States that...
A medical researcher wanted to estimate the proportion of all births in the United States that were by caesarian section. A random sample of 200 births showed that 48 were by caesarian section. Create a confidence interval at 90% confidence for the proportion of all US births that are by caesarian section
An estimate is needed of the mean average of farms in a certain city. A 95%...
An estimate is needed of the mean average of farms in a certain city. A 95% confidence interval should have a margin of error of 29 acres. A study ten years ago inn this city had a sample standard deviation of 110 acres for farm size. About how large a sample of farms is needed?
Use the normal distribution to find a confidence interval for a proportion p given the relevant...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for the proportion who will answer ‘‘Yes” to a question, given that 60 answered yes in a random sample of 95 people. Round your answers to three decimal places. Point estimate = Margin of error...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT