A quality control specialist for a restaurant chain takes a random sample of size 14 to check the amount of soda served in the 16 oz. serving size. The sample mean is 13.30 with a sample standard deviation of 1.58. Assume the underlying population is normally distributed.
Find the 95% confidence interval for the true population mean for the amount of soda served. (Round your answers to two decimal places.)
(____, ____)
we have mean() = 13.30, sample standard deviation (s) = 1.58, sample size(n) = 14
and from student's t distribution table, we can find out the t critical value for degree of freedom =n-1 = 14-1 = 13, we get 2.16
using the formula for confidence interval, we get
Confidence interval =
setting the given values, we get
Confidence interval = = (12.39, 14.21)
So, the required 95% confidence interval for the true population mean fo the amount of sode served is (12.39, 14.21)
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