Question

In a test of the effectiveness of garlic for lowering​ cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes ​(beforeminus​after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 3.7 and a standard deviation of 19.3. Construct a 95​% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL​ cholesterol? Click here to view a t distribution table. LOADING...

What is the confidence interval estimate of the population mean mu​? ​

mg/dLless than muless than mg/dL ​

(Round to two decimal places as​ needed.)

Answer 1

Given :-

Mean ( ) = 3.7

Sample mean (Sx) = 19.3

Sample size (n) = 49

Here using ti-83 calculator.

95% confidence interval for population mean is

-1.84 mg/dL < mu < 9.24 mg/dL