A normal distribution has a standard deviation equal to 26. What is the mean of this normal distribution if the probability of scoring above
x = 183
is 0.0228? (Round your answer to one decimal place.)
You may need to use the appropriate table in Appendix C to answer
this question.
https://www.webassign.net/priviterastats3/priviterastats3_appendix_c.pdf
Solution:-
Given that,
x = 183
standard deviation = = 26
Using standard normal table,
P(Z > z) = 0.0228
= 1 - P(Z < z) = 0.0228
= P(Z < z) = 1 - 0.0228
= P(Z < z ) = 0.9772
= P(Z < 2.00 ) = 0.9772
z = 2.00
Using z-score formula,
x = z * +
183 = 2.00 * 26 +
= 183 - 52
= 131
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