Question

There are 8 black balls and 7 red balls in an urn. If 4 balls are drawn without replacement, what is the probability that no more than 1 black ball is drawn? Express your answer as a fraction or a decimal number rounded to four decimal places.

Answer #1

**Solution:**

Total number of balls = 8 + 7 = 15

Number of red balls = 8

Number of black balls = 7

4 balls are drawn without replacement.

**Case
(1):**

**0 black ball is
drawn:**

This implies that all 4 balls are red.

Hence, total number of ways =

**Case
(2):**

**1 black ball is
drawn:**

This implies that 3 balls are red and 1 balls is black.

Hence, total number of ways =

Total number of ways of drawing 4 balls from a bag of 15 balls =

Hence, probability that no more than 1 black ball is drawn =

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a decimal number rounded to four decimal places.

There are 6 black balls and 5 red balls in an urn. If 4 balls
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decimal number rounded to four decimal places.

There are 5 black balls and 10 red balls in an urn. If 3 balls
are drawn without replacement, what is the probability that no
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decimal number rounded to four decimal places.

Urn 1 contains 7 red balls and 3 black balls. Urn 2 contains 4
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enter your answer as a decimal rounded to 3 decimal places

Urn 1 contains 7 red balls and 3 black balls. Urn 2 contains 1
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Enter your answer as a fraction in simplest form or a decimal
rounded to 3 decimal places.

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Enter your answer as a fraction in simplest form or a decimal
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P(red)=

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