There are 8 black balls and 7 red balls in an urn. If 4 balls are drawn without replacement, what is the probability that no more than 1 black ball is drawn? Express your answer as a fraction or a decimal number rounded to four decimal places.
Solution:
Total number of balls = 8 + 7 = 15
Number of red balls = 8
Number of black balls = 7
4 balls are drawn without replacement.
Case (1):
0 black ball is drawn:
This implies that all 4 balls are red.
Hence, total number of ways =
Case (2):
1 black ball is drawn:
This implies that 3 balls are red and 1 balls is black.
Hence, total number of ways =
Total number of ways of drawing 4 balls from a bag of 15 balls =
Hence, probability that no more than 1 black ball is drawn =
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