Assume that the marks of students in Statistical Methods are normally distributed. A random sample of 25 students’ marks yields a sample mean of 70 and a sample standard deviation of 10. (a) Estimate the population mean of the marks with 95% confidence.
(b) If the population mean of the marks is 67 and the probability that the sample mean of 25 students’ marks is greater than 70 is 3%, find the population standard deviation of the marks
a) For n - 1 = 24 degrees of freedom, we get from the t distribution tables that:
P( -2.064 < t24 < 2.064 ) = 0.95
Therefore the 95% confidence interval for mean here is obtained as:
This is the required 95% confidence interval for the population mean
b) Here, we are given that:
From central limit theorem, we have the distribution of the sample mean as:
Now, we have:
From standard normal tables, we have:
P(Z > 1.881 ) = 0.03
Therefore, we get the z score here as 1.881
So, we get:
Therefore the population standard deviation of marks is 7.9745
Get Answers For Free
Most questions answered within 1 hours.