The accompanying table contains two samples that were collected as matched pairs. Complete parts a and b below.
Pair | Sample 1 | Sample 2 |
1 | 10 | 4 |
2 |
6 | 7 |
3 | 4 | 6 |
4 | 8 | 3 |
5 | 11 | 5 |
6 | 7 | 9 |
7 | 8 | 5 |
8 | 7 | 5 |
A.
Construct a 90?% confidence interval to estimate difference in means between the populations from which Sample 1 and 2 were drawn.
UCL d-overbar |
= ?? |
|
LCL d-overbar |
= ?? |
B . What conclusions can be made?
The interval "does not include OR does include" ?zero, so there "is OR is not" enough evidence to conclude that there is a difference in means between the populations from which Sample 1 and 2 were drawn.
A)
t value at 90% = 1.8946
Sample 1 Sample2 dbar
10 4 6
6 7 -1
4 6 -2
8 3 5
11 5 6
7 9 -2
8 5 3
7 5 2
dbar = ?(sample1) - ?(sample2)
= 7.625 - 5.5
= 1.7
s(dbar) = 2.1998 - 1.8516
= 3.1640
SE = s(dbar)/sqrt(n) = 1.1187
CI = dbar +/- t *SE
= 1.7 +/- 1.8946 *1.1187
= (-0.4194 , 3.8194 )
B)
The interval "does include" ?zero, so there "is" enough evidence to conclude that there is a difference in means between the populations from which Sample 1 and 2 were drawn.
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