Question

The distribution of adult men’s heights is approximately normally distributed with mean 175.0 cm and standard...

The distribution of adult men’s heights is approximately normally distributed with mean 175.0 cm and standard deviation 6.40 cm. State answers rounded to one place of decimal. [4] a) Approximately what percentage of men are taller than 183 cm? b) What height is such that approximately 90% of men are taller than this height?

Homework Answers

Answer #1

Given,

= 175, = 6.4

We convert this to standard normal as

P(X < x) = P( Z < x - / )

a)

P( X > 183) = P( Z > 183 - 175 / 6.4)

= P( Z > 1.25)

= 1 - P( Z < 1.25)

= 1 - 0.8944

= 0.1056

= 10.6%

b)

We have to calculate x such that

P( X > x) = 0.90

That is P( X < x) = 0.10

P( Z < x - / ) = 0.10

From the Z table, z-score for the probability of 0.10 is -1.2816

x - / = -1.2816

Put the values of and in above equation and solve for x

x - 175 / 6.4 = -1.2816

x = 166.8

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