Question

Think about a situation in your life that can be modeled by the binomial probability distribution; it is ok to come up with a rough estimate of the probability of a success in your situation. For example, my cell phone drops my calls roughly 10% of the time (a “success” in this situation is a dropped call, and a “failure” is an un-dropped call; the probability of a success is p=0.10); I made 10 phone calls last month (fixed number of trials is n=10); whether or not a phone call gets dropped is independent of any other phone call I make. The probability of 4 successes, or 4 dropped calls, is P(4)=10!6!4!⋅(0.1)4⋅(0.9)6=0.0112

P(4)=10!6!4!.(0.1)4⋅(0.9)6=0.0112

Tell us the binomial situation you come up with and calculate the probability of 4 successes out of 10 trials (it is fine to estimate the probability of one success like I did above).

Answer 1

Above solution is correct with full explaination so please rate me high .