Question

According to a reputable magazine, 32% of all cars sold in a certain country are SUVs. Suppose a random sample of 500 recently sold cars shows that 146 are SUVs.

Z=?

p(value)=?

Answer 1

Claim : 32% of all cars sold in a certain country are SUV's.

H₀ : P = 0.32

H_a : P ≠ 0.32

Let x be the number of sold cars are SUV's and n is random sample

So we are given x = 146 and n = 500

Z =   ; = x /n = 146/500 = 0.2920 and q = 1- P = 1-0.32 = 0.68

=

z = -1.34

P- value = 2*P( z <-1.34 )

P( z <-1.34 ) = 0.0901 ---- ( from z score table , table value corresponding to -1.34 )

=2*0.0901

P- value = 0.1802