Suppose that the amount of time INTI International University
students spend in the library
per week is normally distributed. A sample of 6 students is
selected at random, and the
sample mean computed as 13.83 hours with the standard deviation of
2.86 hour. Test at 1%
significance level whether the mean number of hours spend in the
library per week is less
than 15 hours.
Solution :
This is the left tailed test,
The null and alternative hypothesis is ,
H0 : = 15
Ha : < 15
Test statistic = t =
= ( - ) / s / n
= (13.83 - 15 ) / 2.86 / 6
Test statistic = t = -1.00
degrees of freedom = n - 1 = 6 - 1 = 5
P(t < -1.00)
P-value = 0.1816
= 0.1
P-value >
Fail to reject the null hypothesis .
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