Question

A random sample of 42 firms was chosen from the S&P 500 firms listed in the...

A random sample of 42 firms was chosen from the S&P 500 firms listed in the Spring 2003 Special Issue of Business Week (The Business Week Fifty Best Performers). The indicated dividend yield (DIVYIELD), the earnings per share (EPS), and the stock price (PRICE) were recorded for these 42 firms.† These data are available in the worksheet entitled DIV4. Run a regression using DIVYIELD as the dependent variable and EPS and PRICE as the independent variables. Use the output to answer the following questions.

(a) What is the sample regression equation relating DIVYIELD to PRICE and EPS? (Round your answers to three decimal places.)

DIVYIELD =  +  PRICE +  EPS

(b) What percentage of the variation of DIVYIELD has been explained by the regression? (Round your answer to two decimal places.)

%

(c) Test the overall fit of the regression. Use a 10% level of significance.
State the hypotheses to be tested.

H0: β1 = β2 = 0
Ha: At least one of the coefficients is not equal to 0.H0: At least one of the coefficients is not equal to 0.
Ha: β1 = β2 = 0    H0: None of the coefficients are equal to zero.
Ha: β1 = β2 = 0H0: β1 = β2 = 0
Ha: None of the coefficients are equal to zero.


State the decision rule.

Reject H0 if p < 0.10.
Do not reject H0 if p ≥ 0.10.Reject H0 if p > 0.05.
Do not reject H0 if p ≤ 0.05.    Reject H0 if p > 0.10.
Do not reject H0 if p ≤ 0.10.Reject H0 if p < 0.05.
Do not reject H0 if p ≥ 0.05.


State the appropriate test statistic name, degrees of freedom, test statistic value, and the associated p-value (Enter the degrees of freedom as a whole number, the test statistic value to three decimal places, and the p-value to four decimal places).

---Select--- μ z G F t (  ,  ) = , p ---Select--- ≤ ≥ < > =  

(d) What conclusion can be drawn from the test result?

Do not reject H0. Neither variable appears to be useful in explaining the variation in dividend yield.Do not reject H0. At least one of the coefficients is equal to zero. The model is not useful in explaining the variation in dividend yield.    Reject H0. At least one of the coefficients is equal to zero. The model is not useful in explaining the variation in dividend yield.Reject H0. Neither variable appears to be useful in explaining the variation in dividend yield.


(e) Is it necessary to test each coefficient individually to see if either PRICE or EPS is related to DIVYIELD? Why or why not?

Yes. Since we tested them together, we can only confirm that at least one coefficient is equal to zero.Yes. Since we tested them together, we can only confirm that at least one coefficient is related to DIVYIELD.    No. From the overall fit test we know that both coefficients are related to DIVYIELD.No. From the overall fit we know that neither coefficient is significant.

Company Name DIVYIELD PRICE EPS
Delphi 3.62 8 0.61
Liz Claiborne 0.8 28 2.16
Snap-On 4 14 1.76
Darden Restaurants 0.45 18 1.37
Tribune 0.98 45 1.8
Interpublic Group 3.94 10 0.77
TJX 0.75 16 1.08
Dollar General 1.23 10 0.76
Circuit City Stores 1.58 4 0.57
Winn-Dixie Stores 1.64 12 1.65
Kellogg 3.42 30 1.75
Campbell Soup 3.04 21 1.39
Exxon Mobil 2.7 34 1.61
EOG Resources 0.39 41 0.65
Washington Mutual 3.36 35 4.05
North Fork Bancorporation 3.35 32 2.58
Union Planters 4.85 28 2.59
Bank of New York 3.34 23 1.24
Household International 3.58 28 3.22
Charles Schwab 0.56 8 0.52
American International Group 0.38 49 2.1
Loews 1.37 44 4.65
Simon Property Group 6.93 35 1.93
Stryker 0.18 65 1.7
Baxter International 2.05 28 1.67
Eli Lilly 2.37 57 2.5
Bristol-Myers Squibb 4.81 23 0.12
General Electric 3.16 24 1.51
Rockwell Collins 1.83 20 1.29
Cummins 5.01 24 1.82
First Data 0.23 35 1.62
Deluxe 3.67 40 3.36
Union Pacific 1.67 55 5.05
Autodesk 0.83 14 0.28
Scientific-Atlanta 0.31 13 0.35
International Flavors & Fragrances 1.91 31 1.84
Eastman Chemical 5.47 32 1.02
Alltel 3.22 43 2.96
Dominion Resources 4.79 54 4.82
Cinergy 5.71 32 2.34
Peoples Energy 5.92 36 2.51
Nicor 6.12 30 2.94

Homework Answers

Answer #1

Here we are using regression function of excel

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.295464
R Square 0.087299
Adjusted R Square 0.040494
Standard Error 1.843435
Observations 42
ANOVA
df SS MS F Significance F
Regression 2 12.67655 6.338276 1.865158 0.168425
Residual 39 132.5318 3.398252
Total 41 145.2084
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept 2.450218 0.652922 3.752694 0.000569 1.129558 3.770878 1.129558 3.770878
PRICE -0.02931 0.025961 -1.12902 0.265786 -0.08182 0.023201 -0.08182 0.023201
EPS 0.604067 0.313829 1.92483 0.061567 -0.03071 1.238846 -0.03071 1.238846

Here the equation is

DIVYIELD = 2.45022 - 0.02931 * Price + 0.6041 * EPS

(b) Here

R2= 0.0873

so here8.73 percentage of the variation of DIVYIELD has been explained by the regression.

(c)

H0: β1 = β2 = 0
Ha: At least one of the coefficients is not equal to 0

Do not reject H0 if p ≥ 0.10.

associted p - value = 0.16 which is greater than 0.10 so p > 0.10

State the appropriate test statistic name is F test

degrees of freedom

Regression = 2

Residual = 39

Test statistic value = F = 1.865

Associated p-value = 0.1684

(d)

Do not reject H0. Neither variable appears to be useful in explaining the variation in dividend yield.

(e) No. From the overall fit we know that neither coefficient is significant.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider a portion of simple linear regression results, y^ = 104.93 + 24.73x1; SSE = 407,297;...
Consider a portion of simple linear regression results, y^ = 104.93 + 24.73x1; SSE = 407,297; n = 30 In an attempt to improve the results, two explanatory variables are added. The relevant regression results are the following: y^ = 4.80 + 19.21x1 – 25.62x2 + 6.64x3; SSE = 344,717; n = 30. [You may find it useful to reference the F table.] a. Formulate the hypotheses to determine whether x2 and x3 are jointly significant in explaining y. H0:...
For a sample of 20 New England cities, a sociologist studies the crime rate in each...
For a sample of 20 New England cities, a sociologist studies the crime rate in each city (crimes per 100,000 residents) as a function of its poverty rate (in %) and its median income (in $1,000s). A portion of the regression results is as follows. ANOVA df SS MS F Significance F Regression 2 3,113.6 1,556.8 0.25 0.779 Residual 17 104,444.27 6,143.78 Total 19 107,557.8 Coefficients Standard Error t Stat p-value Intercept 843.6066 128.6559 6.557 0.000 Poverty −3.3654 5.1734 −0.6510...
You may need to use the appropriate technology to answer this question. In a regression analysis...
You may need to use the appropriate technology to answer this question. In a regression analysis involving 30 observations, the following estimated regression equation was obtained. ŷ = 17.6 + 3.8x1 − 2.3x2 + 7.6x3 + 2.7x4 For this estimated regression equation, SST = 1,835 and SSR = 1,790. (a) At α = 0.05, test the significance of the relationship among the variables. State the null and alternative hypotheses. H0: One or more of the parameters is not equal to...
In a regression analysis involving 30 observations, the following estimated regression equation was obtained. ŷ =...
In a regression analysis involving 30 observations, the following estimated regression equation was obtained. ŷ = 17.6 + 3.8x1 − 2.3x2 + 7.6x3 + 2.7x4 For this estimated regression equation, SST = 1,815 and SSR = 1,780. (a) At α = 0.05, test the significance of the relationship among the variables. State the null and alternative hypotheses. H0: β0 = β1 = β2 = β3 = β4 = 0 Ha: One or more of the parameters is not equal to...
In a regression analysis involving 27 observations, the following estimated regression equation was developed. ŷ =...
In a regression analysis involving 27 observations, the following estimated regression equation was developed. ŷ = 25.2 + 5.5x1 For this estimated regression equation SST = 1,550 and SSE = 530. (a) At α = 0.05, test whether x1  is significant.State the null and alternative hypotheses. H0: β1 ≠ 0 Ha: β1 = 0 H0: β0 ≠ 0 Ha: β0 = 0    H0: β0 = 0 Ha: β0 ≠ 0 H0: β1 = 0 Ha: β1 ≠ 0 Find the value...
In a regression analysis involving 27 observations, the following estimated regression equation was developed. ŷ =...
In a regression analysis involving 27 observations, the following estimated regression equation was developed. ŷ = 25.2 + 5.5x1 For this estimated regression equation SST = 1,600 and SSE = 550. (a) At α = 0.05, test whether x1is significant.State the null and alternative hypotheses. H0: β0 = 0 Ha: β0 ≠ 0 H0: β0 ≠ 0 Ha: β0 = 0    H0: β1 ≠ 0 Ha: β1 = 0 H0: β1 = 0 Ha: β1 ≠ 0 Find the value...
For a sample of 20 New England cities, a sociologist studies the crime rate in each...
For a sample of 20 New England cities, a sociologist studies the crime rate in each city (crimes per 100,000 residents) as a function of its poverty rate (in %) and its median income (in $1,000s). A portion of the regression results is as follows. Use Table 2 and Table 4. ANOVA df SS MS F Significance F   Regression 2    188,246.8 94,123.4 9.04E-07      Residual 17    45,457.32   2,673.96   Total 19    233,704.1 Coefficients Standard Error t Stat p-value...
For a sample of 20 New England cities, a sociologist studies the crime rate in each...
For a sample of 20 New England cities, a sociologist studies the crime rate in each city (crimes per 100,000 residents) as a function of its poverty rate (in %) and its median income (in $1,000s). A portion of the regression results is shown in the accompanying table. Use Table 2 and Table 4. ANOVA df SS MS F Significance F Regression 2 294.3 147.2 9.73E-01 Residual 17 91,413.94 5,377.29 Total 19 91,708.30 Coefficients Standard Error t Stat p-value Lower...
You may need to use the appropriate technology to answer this question. In a regression analysis...
You may need to use the appropriate technology to answer this question. In a regression analysis involving 27 observations, the following estimated regression equation was developed. ŷ = 25.2 + 5.5x1 For this estimated regression equation SST = 1,550 and SSE = 590. (a) At α = 0.05, test whether x1 is significant. State the null and alternative hypotheses. H0: β0 ≠ 0 Ha: β0 = 0 H0: β1 = 0 Ha: β1 ≠ 0    H0: β0 = 0 Ha:...
In a regression analysis involving 27 observations, the following estimated regression equation was developed. ŷ =...
In a regression analysis involving 27 observations, the following estimated regression equation was developed. ŷ = 25.2 + 5.5x1 For this estimated regression equation SST = 1,600 and SSE = 550. (a) At α = 0.05, test whether x1 is significant. State the null and alternative hypotheses. H0: β0 = 0 Ha: β0 ≠ 0H0: β0 ≠ 0 Ha: β0 = 0    H0: β1 ≠ 0 Ha: β1 = 0H0: β1 = 0 Ha: β1 ≠ 0 Find the value of...