Question

1-sample proportions test without continuity correction

data:  138 out of 300, null probability 0.35
X-squared = 15.956, df = 1, p-value = 1
A consulting firm had predicted that 35% of the employees at a large firm would take advantage of a new company Credit Union., but management is skeptical. They doubt the rate is that high. A survey of 300 employees shows that 138 of them are currently taking advantage of the Credit Union.

Use R to carry out an appropriate test. Interpret the result at a significance level 0.05.
1. How to conclude this:

alternative hypothesis: true p is less than 0.35
95 percent confidence interval:
 0.0000000 0.5074775
sample estimates:
   p 
0.46 

Answer 1

This problem is solved by using R

Output is :

Thank You!