Question

1-sample proportions test without continuity correction data: 138 out of 300, null probability 0.35 X-squared = 15.956, df = 1, p-value = 1 A consulting firm had predicted that 35% of the employees at a large firm would take advantage of a new company Credit Union., but management is skeptical. They doubt the rate is that high. A survey of 300 employees shows that 138 of them are currently taking advantage of the Credit Union. Use R to carry out an appropriate test. Interpret the result at a significance level 0.05. 1. How to conclude this: alternative hypothesis: true p is less than 0.35 95 percent confidence interval: 0.0000000 0.5074775 sample estimates: p 0.46

Answer #1

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Output is :

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