Question

3. A survey was conducted about the cost for a family of four to visit an...

3. A survey was conducted about the cost for a family of four to visit an amusement park for one day. A sample

of 32 families yielded an average cost of $190.28 with a standard deviation of $51.75. Last year, a magazine

published that the average cost for a family of four to visit an amusement park was $175. Based on the sample

data above, can we conclude that the mean cost is actually higher than this at α=0

3. According to a large local high school, senior students have a mean GPA of 3.07. A random sample of 38

seniors taking AP courses showed a mean GPA of 3.29 with a standard deviation of 0.42. At the 1% level of

significance, can it be stated that seniors taking AP courses have a different GPA than the senior class as a

whole?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. A statistician is interested in the gross earnings of several of her favorite bands. She...
1. A statistician is interested in the gross earnings of several of her favorite bands. She took a random sample of 30 of the Rolling Stones’ North American concerts, and found that the gross earnings averaged $2.27 million with a standard deviation of $0.5 million. One source suggests that the average gross earnings per concert for every stadium performance in North America is $2.11 million. Do the Rolling Stones earn more on average? Test at a 5% level of significance...
A survey conducted by the American Automobile Association showed that a family of four spends an...
A survey conducted by the American Automobile Association showed that a family of four spends an average of $215.60 per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of $252.45 per day and a sample standard deviation of $69.50. a. Develop a 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls (to 2 decimals). ( , )...
A survey conducted by the American Automobile Association showed that a family of four spends an...
A survey conducted by the American Automobile Association showed that a family of four spends an average of $215.60 per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of $252.45 per day and a sample standard deviation of $75.50. a. Develop a 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls (to 2 decimals). (  ,  ) b. Based...
A survey conducted by the American Automobile Association showed that a family of four spends an...
A survey conducted by the American Automobile Association showed that a family of four spends an average of $215.60 per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of $252.45 per day and a sample standard deviation of $78.50. a. Develop a 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls (to 2 decimals). ( ___ ,...
A survey conducted by the American Automobile Association showed that a family of four spends an...
A survey conducted by the American Automobile Association showed that a family of four spends an average of $215.60 per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of $252.45 per day and a sample standard deviation of $74.50. a. Develop a 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls (to 2 decimals). (____,_____) b. Based...
According to a survey conducted by the American Automobile Association, a family of four spends an...
According to a survey conducted by the American Automobile Association, a family of four spends an average of $255.60 per day while on vacation in the US. Suppose a sample of 36 families of four vacationing at Mount Rushmore resulted in a sample mean of $235.31 per day and a sample standard deviation of $53.50. a) Develop a 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Mount Rushmore (round to two...
            A local resort claims that the average family spends less than $1,200 on a weekend...
            A local resort claims that the average family spends less than $1,200 on a weekend stay at its facility. A magazine that reviews vacation destinations investigated this result by taking a a random sample of 19 families that have stayed at the resort in the last year. The sample produced a mean of $1224.939 and a standard deviation of $62.69. For the hypotheses:             H0: µ = $1,200    and   HA: µ > $1,200, what is the p-value of the...
Proctor & Gamble reported that an American family of four washes an average of 1 ton...
Proctor & Gamble reported that an American family of four washes an average of 1 ton (2000) pounds of clothes each year. If the standard deviation of the distribution is 187.5 pounds, find the probability that the mean of a randomly selected sample of 50 families of four will be between 1980 and 1995 pounds. Round final answer to 4 decimal places (0.0001).
Procter & Gamble reported that an American family of four washes an average of 2100 pounds...
Procter & Gamble reported that an American family of four washes an average of 2100 pounds of clothes each year. If the standard deviation of the distribution is 187.5 pounds, find the probability that the mean of a randomly selected sample of 50 families will be a. between 2020 and 2150 pounds b. less than 2130 pounds c. greater than 2050 pounds
A survey found that the American family generates an average of 17.2 pounds of glass garbage...
A survey found that the American family generates an average of 17.2 pounds of glass garbage each year. Assume the standard deviation of the distribution is 2.5 pounds. Find the probability that the mean of a sample of 45 families will be between 16 and 17 pounds. Assume that the sample is taken from a large population and the correction factor can be ignored. Use a TI-83 Plus/TI-84 Plus calculator and round the final answers to at least four decimal...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT