Compute the reliability of a system with 4 components in standby parallel configuration, with failure rate of 0.000346 after 7600 hours of operation
ANSWER: 0.729547242
PLEASE SHOW ALL WORK
When all components have the same failure rate lambda = 0.00346, then the reliability of the system for the parallel components is given by,
Reliability of the standby system with 4 standby components = 1 - (1-R)4
R=Reliability of each component R(t) = e^{-t}
The correct answer is this, not the one which was given with the question.
Get Answers For Free
Most questions answered within 1 hours.