Question

Below is a data set presented in a Frequency Table

Data Value	Frequency
2	59
5	63
9	28
12	41
15	109

Find the following for the data set above:

a.) Mode =

b.) Median =

c.) Mean =  (Round to TWO decimal places)

Answer 1

half of the Frequency is 300/2 = 150

Cumulative frequency total is 600. we need to find which cumulative data set has greater than or equal to 150

data value 9 is showing 150 cumulative value.

so data set 9 is the median