a) P(X < 45) = P(z < (45-52)/5) = P(z < -1.4) = 0.0808 (Percentile)
b) P(X > 54) = P(z > (54 - 45)/5) = P(z > 1.8) = 1 -
P(z < 1.8) = 1 - 0.9641 = 0.0359
3.59% would receive a higher score
c) P(X < 148) = P(z < (148 - 125)/15) = P(z < 1.53) = 0.9370 (Percentile rank)
d) P(X < 94) - P(X < 76) = P(z < (94 - 80)/8) - P(z
< (76 - 80)/8) = P(z < 1.75) - p(z < -0.5)
= 0.9599 - 0.3085 = 0.6514
Hence, 65.14% would score between Pat and Chris
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