A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14 years, and standard deviation of 2.6 years. If you randomly purchase one item, what is the probability it will last longer than 8 years?
Given that ,
mean = = 14
standard deviation = = 2.6
n = 1
= 14
= / n =2.6 / 1 = 2.6
P( >8 ) = 1 - P( <8 )
= 1 - P[( - ) / < (8 -14) /2.6 ]
= 1 - P(z <-2.31 )
Using z table
= 1 - 0.0104
= 0.9896
probability= 0.9896
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