Question

LET'S SAY THESE ARE THE NUMBER OF STRIKE-OUTS A PITCHER THROWS IN THE NUMBER OF INNINGS...

LET'S SAY THESE ARE THE NUMBER OF STRIKE-OUTS A PITCHER THROWS IN THE NUMBER OF INNINGS PITCHED (WE HAVE 6 PAIRS OF DATA POINTS SO n = 6)

THE INNINGS PITCHED ARE THE ''X'' VALUES (INDEPENDENT VARIABLE) AND THE STRIKE-OUTS ARE THE ''Y'' VALUES (DEPENDENT VARIABLE)

FOR EXAMPLE WHEN PITCHING 4 INNINGS, THE PITCHER STRUCK OUT 6 BATTERS (4,6) (ETC.)

DATA POINTS (X,Y) X Y X - Mx (X-Mx)^2 Y - My (X-Mx)*(Y-My)
(4,6)
(3,7)
(5,12)
(11,17)
(10,10)
(14,14)
MEAN (Mx & My) TOTAL TOTAL
SD

SO, USING THIS EQUATION, HOW MANY STRIKE-OUTS WOULD BE PREDICTED FOR THIS PITCHER IN X = 8 INNINGS?

Homework Answers

Answer #1
X Y X-Mx (X-Mx)^2 Y - My (Y - My)^2 (X - Mx)(Y-My)
4 6 -3.83333 14.69444 -5 25 19.16667
3 7 -4.83333 23.36111 -4 16 19.33333
5 12 -2.83333 8.027778 1 1 -2.83333
11 17 3.166667 10.02778 6 36 19
10 10 2.166667 4.694444 -1 1 -2.16667
14 14 6.166667 38.02778 3 9 18.5
Total 47 66 98.83333 88 71
Mean 7.833333 11
SD 4.445972 4.195235

= 98.33

= 88

= 71

let the simple linear regression equation be y = b0 + b1x

b1 = Sxy/Sxx = 71/98.33 = 0.722

b0 = My - b1Mx = 11 - 0.722*7.83 = 5.35

Y = 5.35 + 0.722X

for X =8 Y = 5.35 + 0.722*8 = 11.12

Y = 11.

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