You wish to test the following claim ( H a ) at a significance level of α = 0.01 . d denotes the mean of the difference between pre-test and post-test scores. H o : μ d = 0 H a : μ d < 0 You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:
post-test: 51.5, 61.4, 54.2, 49.8, 47, 55.4, 50.3, 48, 47.6, 51.4, 44.2, 54.8, 56, 47.8, 53.3, 51.1
pre-test : 34.2, 28.5, 53.3, 78.9, 30.1, 28.8, 11.5, 17.4, 11.1, 25.3, 32.8, 43.4, 57.5 , 54.3,54.8 , 55.3
What is the test statistic for this sample?
What is the p-value for this sample? Round to 4 decimal places.
The table is as follows:
Pre-Test | Post-test | d (Difference = Post-test - Pre-test) |
34.2 | 51.5 | 17.3 |
28.5 | 61.4 | 32.9 |
53.3 | 54.2 | 0.9 |
78.9 | 49.8 | -29.1 |
30.1 | 47 | 16.9 |
28.8 | 55.4 | 26.6 |
11.5 | 50.3 | 38.8 |
17.4 | 48 | 30.6 |
11.1 | 47.6 | 36.5 |
25.3 | 51.4 | 26.1 |
32.8 | 44.2 | 11.4 |
43.4 | 54.8 | 11.4 |
57.5 | 56 | -1.5 |
54.3 | 47.8 | -6.5 |
54.8 | 53.3 | -1.5 |
55.3 | 51.1 | -4.2 |
d-bar = 12.91
sd = 18.86
The test statistic formula is:
t = (12.91 - 0)/(18.86/√16)
t = 12.91/4.715 = +2.74
The p-value associated with t = 2.74 and df = n - 1 = 15 is 0.0076.
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