cards numbered from 1 through 31 are placed into a box and two cards are selected without replacement. Find the probability that both numbers selected are odd, given that their sum is even.
Find the probability that both numbers selected are odd, given that their sum is even.
Given that the sum of the 2 numbers is even, it is possible when either both the numbers are even or both are odd. Therefore number of ways to select 2 numbers such that the sum if even is computed as:
= Number of ways to select 2 even numbers + Number of ways to select 2 odd numbers
Probability that both numbers selected are odd given that the sum of two numbers is even is computed as:
= Number of ways to select two odd numbers / Total number of ways to get sum as even
Therefore 0.5333 is the required probability here.
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