(a) One day, upon tossing a single die 180 times, I got: 32 ones, 28 twos, 35 threes, 36 fours, 29 fives, and 20 sixes. Computer χ2 and find P for this experiment.
(b) Another day, upon tossing a single die 120 times, I got: 12 ones, 26 twos, 20 threes, 21 fours, 15 fives, and 26 sixes. Computer χ2 and find P for this experiment.
(c). Now, computer the pooled χ2 using the combined degrees of freedom, and find the pooled P-values
(a) Here χ2 =
Roll | Frequency | Expected | χ2 |
1 | 32 | 30 | 0.133 |
2 | 28 | 30 | 0.133 |
3 | 35 | 30 | 0.833 |
4 | 36 | 30 | 1.2 |
5 | 29 | 30 | 0.033 |
6 | 20 | 30 | 3.333 |
Total | 180 | 180 | 5.667 |
Here degree of freedom = dF = 6 -1 = 5
P - value = CHIINV(5.667, 5) = 0.3400
(b) Now here
Roll | Frequency | Expected | χ2 |
1 | 12 | 20 | 3.2 |
2 | 26 | 20 | 1.8 |
3 | 20 | 20 | 0 |
4 | 21 | 20 | 0.05 |
5 | 15 | 20 | 1.25 |
6 | 26 | 20 | 1.8 |
Total | 120 | 120 | 8.1 |
χ2 = 8.1
dF = 6 -1 = 5
P - value = CHIINV(8.1, 5) = 0.1508
(c) Now adding
Here using pooled chi-square we get following table
Roll | Frequency | Expected | χ2 |
1 | 44 | 50 | 0.72 |
2 | 54 | 50 | 0.32 |
3 | 55 | 50 | 0.5 |
4 | 57 | 50 | 0.98 |
5 | 44 | 50 | 0.72 |
6 | 46 | 50 | 0.32 |
Total | 300 | 300 | 3.56 |
χ2 = 3.56
dF = 6 -1 = 5
P - value = CHIINV(3.56, 5) = 0.6143
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