1. Assume that adults have IQ scores that are normally distributed with a mean of μ=100 and a standard deviation σ=15.
Find the probability that a randomly selected adult has an IQ less than 130.
2. Assume the readings on thermometers are normally distributed with a mean of 0 °C and a standard deviation of 1.00 °C.
Find the probability P=(−1.95<z<1.95), where z is the reading in degrees.
3. Women's heights are normally distributed with mean 63.3 in and standard deviation of 2.5 in. A social organization for tall people has a requirement that women must be at least
69 in tall. What percentage of women meet that requirement?
1)
Given,
= 100 , = 15
We convert this to standard normal as
P( X < x) = P( Z < x - / )
P( X < 130) = P( Z < 130 - 100 / 15)
= P( Z < 2 )
= 0.9772
b)
P(-1.95 < Z < 1.95) = P( Z < 1.95) - P( Z < -1.95)
= 0.9744 - ( 1 - 0.9744)
= 0.9488
c)
Given,
= 63.3 , = 2.5
We convert this to standard normal as
P( X < x) = P( Z < x - / )
P( X >= 69) = P( Z >= 69 - 63.3 / 2.5)
= P( Z >= 2.28)
= 1 - P( Z < 2.28)
= 1 - 0.9887
= 0.0113
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