Use the given confidence level and sample data to find a confidence interval for the population standard deviation sigma . Assume that a simple random sample has been selected from a population that has a normal distribution.
Salaries of college professors who took a philosophy course in college
95 % confidence; n = 91, x overbar = $65,200, s = $16,815
Chi-square critical value at 0.05 level with 90 df = L = 65.647 , U= 118.136
95% confidence interval for is
sqrt [ (n-1) S2 / U ] < < sqrt [ (n-1) S2 / L ]
sqrt [ 90 * 168152 / 118.136] < < sqrt [ 90 * 168152 / 65.647]
14677 < < 19688
95% CI is ( 14677 , 19688)
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